A sample of 25 adult elephants had an average weight of 9,500 pounds, with a sample standard deviation of 150 pounds. Find the 99% confidence interval of the true mean. Assume that the variable is normally distributed.
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Given the mean weight ,m=9500
Critical value for the 99% confidence interval is z= 2.58.
We have the standard deviation ,d=150
So the formula for the confidence interval is
Upper limit =9584
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