Consider the following reaction:
2HF(g) H2(g) + F2(g) (Kc = 1.00 x 10–2)
Given that 1.00 mol of HF(g), 0.371 mol of H2(g), and 0.750 mol of F2(g) are mixed in a 5.00-L flask, determine the reaction quotient, Q.
d. Q = 2.12
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[HF(g)] = 1/5 = 0.2M
[H2(g)] = 0.371/5 = 0.0742 M
[F2(g)] = 0.750/5 =0.150 M
This reaction quotient = 0.0742*0.150/(0.2*0.2) = 0.278
Hence correct answer is (b)
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