Thank you for the opportunity to help you with your question!
μsw is the coefficient between the ladder and the wall in our problem this is zero
μsf is the coefficient between the ladder and the floor
a = θ angle
thus tanθ= 1 / 2μsf => μsf = 1/ 2tanθPlease let me know if you need any clarification. I'm always happy to answer your questions.
I was wrong the correct problem is here
the coefficitent will be μ = ( m1 * d + m2 * L/2 ) cos(θ) / (m1 + m2) L sin(θ)
the correct forces diagram which accounts for the masses m1 and m2 is in the image
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