Need engineering help to Compute the area of the triangle with the given vertices2

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Qnav6

Engineering

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1/AB=square root (4-2)^2+(-2-1)^2+(6-4)^2=square root 6

AB=2.45

BC=squareroot (4-5)^2+(-2-0)^2

=squareoot 21

1/2ABsinC

b^2=a^2+c^2-2acCos a

ANS =3.354 units squared

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