# Need math help with the probability of an event

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### Question Description

 An ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of arandom experiment.Compute the probability of each of the following events:Event A: The sum is greater than 7.Event B: The sum is an even number.Write your answers as exact fractions.

JamesM847
School: UT Austin

there are 36 out comes when throw the die twice,

the sum is

1times: 12 = 6+6,

2 times 11=5+6 = 6+5

3 times 10 = 5+5 = 4+6=6+4

4 times  9 = 4+5 = 5+4 =6+3 =3+6

5 times 8 = 4+4= 6+2=2+6=5+3=3+5

6 times 7 = 1+6=6+1=5+2=2+5=3+4=4+3

5 times 6 = 3+3=2+4=4+2=1+5=5+1

4 times 5 = 3+2=2+3=1+4=4+1

3 times 4 = 2+2=1+3=3+1

2 time 3 = 1+2=2+1

1 times 2 =1+1

The sum >7, it can be 8, 9, 10, 11 and 12

number of times that the sum> 6 is 1+2+3+4 +5=15

The probability of Event A= 15/36 = 5/12

Fro event B the sum can be 12, 10, 8,,6, 4,2

the times that B occurs is 1+3+5+5+3+1 = 18

The probability of Event B = 1/2

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Anonymous
Tutor went the extra mile to help me with this essay. Citations were a bit shaky but I appreciated how well he handled APA styles and how ok he was to change them even though I didnt specify. Got a B+ which is believable and acceptable.

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