 # Need math help with the probability of an event Anonymous
timer Asked: Nov 11th, 2015
account_balance_wallet \$5

### Question Description

An ordinary (fair) die is a cube with the numbers

through
on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of arandom experiment.

Compute the probability of each of the following events:
Event
: The sum is greater than
.
Event
: The sum is divisible by
.

JamesM847
School: UIUC   Thank you for the opportunity to help you with your question!

there are 36 out comes when throw the die twice,

the sum is

1times: 12 = 6+6,

2 times 11=5+6 = 6+5

3 times 10 = 5+5 = 4+6=6+4

4 times  9 = 4+5 = 5+4 =6+3 =3+6

5 times 8 = 4+4= 6+2=2+6=5+3=3+5

6 times 7 = 1+6=6+1=5+2=2+5=3+4=4+3

5 times 6 = 3+3=2+4=4+2=1+5=5+1

4 times 5 = 3+2=2+3=1+4=4+1

3 times 4 = 2+2=1+3=3+1

2 time 3 = 1+2=2+1

1 times 2 =1+1

The sum >8, it can be  9, 10, 11 and 12

number of times that the sum> 6 is 1+2+3+4=10

The probability of Event A= 10/36 = 5/18

Fro event B the sum can be 12, 8, 4

the times that B occurs is 1+5+3 = 9

The probability of Event B = 9/36=1/4

Please let me know if you need any clarification. I'm always happy to answer your questions.

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