I need help with an algebra problem

label Algebra
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write the equation of a line the passes through the point (7,-2) and is perpendicular to the line x+3y=15

Nov 12th, 2015

Thank you for the opportunity to help you with your question!

For perpendicular lines

product of slopes = -1

slope of line passing through (7,-2) = -1/(-1/3) = 3

Hence equation of line is,

y = 3x +C

=>-2 = 3*7+C = >C = -23


HENCE REQUIRED EQUATION OF LINE IS

3x -y = 23

Please let me know if you need any clarification. I'm always happy to answer your questions.
Nov 12th, 2015

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Nov 12th, 2015
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Nov 12th, 2015
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