write the equation of a line the passes through the point (7,-2) and is perpendicular to the line x+3y=15
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For perpendicular lines
product of slopes = -1
slope of line passing through (7,-2) = -1/(-1/3) = 3
Hence equation of line is,
y = 3x +C
=>-2 = 3*7+C = >C = -23
HENCE REQUIRED EQUATION OF LINE IS
3x -y = 23
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