##### I need help with algebra problems

 Algebra Tutor: None Selected Time limit: 1 Day

Nov 13th, 2015

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Height of cone, h = x units

Volume of cone, V = $\frac{1}{3}\pi r^2h=\frac{1}{3}\pi r^2x$

But it is given that volume = $3\pi x^3\: \: cubic\: \: units$

Therefore,

$\\ \frac{1}{3}\pi r^2x=3\pi x^3\\ \\ \pi r^2x=9\pi x^3\\ \\ r^2=\frac{9\pi x^3}{\pi x}\\ \\ r^2=9x^2\\ \\ r=\sqrt{9x^2}\\ \\ r=3x\: \: units$

So radius of the cone's base = $3x\: \: units$

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Nov 13th, 2015

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Nov 13th, 2015
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Nov 13th, 2015
Dec 3rd, 2016
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