For each ordered pair, determine whether it its a solution to the system of equa

Algebra
Tutor: None Selected Time limit: 1 Day

Nov 14th, 2015

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8x + 2y = -10 ---(1)

y = -4x - 5 ---(2)


Divide equation (1) by 2

4x + y = -5

y = -4x - 5


So both equations represent the same line.


To check whether each of the given points is a solution, substitute the (x, y) values in equation (2) and check if the points satisfy the equation.


(-2, -3)

Put x = -2 and y = -3 in equation (2)

-3 = -4*(-2) - 5

-3 = 8 - 5

-3 ≠ 3

So (-2, -3) is not a solution.


(6, 1)

Put x = 6 and y = 1 in equation (2)

1 = -4*(6) - 5

1 = -24 - 5

1 ≠ -29

So (6, 1) is not a solution.


(-5, 15)

Put x = -5 and y = 15 in equation (2)

15 = -4*(-5) - 5

15 = 20 - 5

15 = 15

So (-5, 15) is a solution.


(0, -5)

Put x = 0 and y = -5 in equation (2)

-5 = -4*(0) - 5

-5 = 0 - 5

-5 = -5

So (0, -5) is a solution. 

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Please let me know if you need any clarification. I'm always happy to answer your questions.
Nov 14th, 2015

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