 # I need help with a geometry problem Anonymous
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### Question Description alancheng
School: Duke University   The line m, is a horizontal line with the equation y = -3.  Line m serves as the bisector of the segments joining points A to A', B to B', and C to C'.   Where the points A', B', and C' are the newly reflected points of the triangle.

Point A is at (2, -2), Point B is at (7, 3), Point C is at (-2, 3).

Point A' is at (2, a), Point B' is at (7, b), and C is at (-2, c),  where a, b, and c are the y-coordinates we will solve.

I will use the Midpoint Formula    ( -2 + a)/2 = -3  which means the average of the endpoints equals the midpoint coordinate.   (-2 + a) = -6,  a = -4  Therefore  A' is at (2, -4)

(3 + b)/2 = -3,

(3 + b) = -6

b = -9

Therefore B' is at (7, -9)

(3 + c)/2 = -3,

c = -9

Therefore C' is at (-2, -9)

Answer Choice D.)  A' (2, -4),  B'(7, -9), C' (-2, -9)

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Thanks, good work Brown University

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