##### Need math help: how many possible identification numbers are possible?

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A warranty identification number for a certain product consists of a letter of the alphabet followed by a four-digit number. How many possible identification numbers are there if the first digit of the four-digit number must be nonzero?
 A. 234,000 numbers B. 307,000 numbers C. 99,000 numbers D. 6,000 numbers E. 414,000 numbers F. 432,000 numbers
Nov 15th, 2015

Thank you for the opportunity to help you with your question!

Possibilities

Alphabets (A-Z) = 26

First digit (1-9) =9

second,third and fourth digits (0-9) =10 each

Therefore the possible number that can be formed from this combination is,

26*9*10^3 = 234,000

Please let me know if you need any clarification. I'm always happy to answer your questions.
Nov 15th, 2015

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Nov 15th, 2015
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Nov 15th, 2015
Dec 10th, 2016
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