An airplane travels 5912 km against the wind in 8 hours and 7432 km with the wind in same amount of time. What is the rate of the plane in still air and what is the rate of the wind?
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Let the speed of the airplane be x km/hr and the speed of the wind be y km/hr.
Speed of the plane with the wind=x+y km/hr
Speed of the plane against the wind =x-y km/hr
Case 1(With the wind)
Time =8 hr
Distance=Speed*Time =8(x+y) =7432
Speed against the wind =x-y kmph
Time taken =8 hour
Solving the system using elimination,eqn(1)+eqn(2),eliminate y
x=834 kmph(answer)=>Speed of the plane
Speed of the wind=929-834 kmph=95 kmph(answer)
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