Thank you for the opportunity to help you with your question!
The first part of the reactant is
aqueous because compounds containing Nitrate is soluble with no exception.
Potassium Iodide is also aqueous because the Iodine ion is soluble unless
combined with Ag, Hg and PB.
On the product side, Lead Iodide is solid because
Lead is one of the exception compound when formed with Iodine, which makes it
an insoluble compound. Potassium Nitrate on the other hand is aqueous as
Nitrate is soluble with no exception when it is part of a compound.
Please let me know if you need any clarification. I'm always happy to answer your questions.