Need physics help to find the displacement in the following figure.

Tutor: None Selected Time limit: 1 Day

Nov 16th, 2015

Thank you for the opportunity to help you with your question!

First, we can find the speed of the first ball at its bottom through conservation of energy

mgh = .5mv^2 (mass cancels)

(9.8)(.1) = (.5)v^2

v = 1.4 m/s

Then through conservation of momentum we can find the speed the two will have after the collision

(2)(1.4) = (5)(v)

v = .56 m/s

That is the preliminary information we need...

Part A)

To find the frequency, apply  \(T = 2\pi\sqrt{l/g}\)

T = (2pi)(.5/9/8)^.5

T = 1.42 sec

The frequency is the inverse of that. 1/1.42 = .705 Hz

Part B)

Now we can find how high the two masses travel after the collision

mgh = .5mv^2 (again mass cancels)

(9.8)(h) = (.5)(.56)^2

h = .016 m (1.6 cm)

From that, we can find the angular displacement

The hypotenuse is 50 cm

The opposite side from by the triangle made is 50 -1.6 = 48.4 cm

cos(angle) = 48.4/50

angle = 14.53 degrees

Please let me know if you need any clarification. I'm always happy to answer your questions.
Nov 16th, 2015

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