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First, we can find the speed of the first ball at its bottom through conservation of energy
mgh = .5mv^2 (mass cancels)
(9.8)(.1) = (.5)v^2
v = 1.4 m/s
Then through conservation of momentum we can find the speed the two will have after the collision
(2)(1.4) = (5)(v)
v = .56 m/s
That is the preliminary information we need...
To find the frequency, apply
T = (2pi)(.5/9/8)^.5
T = 1.42 sec
The frequency is the inverse of that. 1/1.42 = .705 Hz
Now we can find how high the two masses travel after the collision
mgh = .5mv^2 (again mass cancels)
(9.8)(h) = (.5)(.56)^2
h = .016 m (1.6 cm)
From that, we can find the angular displacement
The hypotenuse is 50 cm
The opposite side from by the triangle made is 50 -1.6 = 48.4 cm
cos(angle) = 48.4/50
angle = 14.53 degrees
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