Calculate the molar solubility of PbCl2 in pure water at 25c. Ksp= 1.17 x 10^-5 (show work please)
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Substitute into the Ksp expression: Ksp=[Pb2+][Cl-]^2, Ksp=(s)(2s)^2
Substitute the value of Ksp into the equation and solve for s: Ksp=4S^3, S=cubic root of (Ksp/4)=cubic root of (1.17*10^-5 / 4)
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