##### I need help with a chemistry problem

label Chemistry
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4.  Determine the molecular weight for the following compounds.

a.       O2 - oxygen

b.       CO – carbon monoxide

c.        NH3 - ammonia

d.       C2H4 - ethylene

e.        C5H2 – pentane

f.        C2H2 – acetylene

g.        C3H80 – isopropyl alcohol

h.       H2SO4 – sulfuric acid

i.         NaOH – sodium hydroxide

Nov 21st, 2015

To determine the molecular weight we should know the atomic mass of each element

 Element Atomic mass H 1.007 C 12.01 O 15.99 S 32.065 N 14.0067

Now using the above atomic mass we can calculate the molecular weight of the above compound as

 Compound Molecular mass O2 2*atomicmass of O=2*15.99=31.9988 CO Atomic mass of C+O=12.01+15.99=28.01 NH3 Atomic mass of N+3*atomic mass of H=14.0067+3*1.007=17.03 C2H4 2*atomic mass of C+4*atomic mass of H=2*12.01+4*1.007=28.0532 C5H2 5*12.01+2*1.007=62.0694 C2H2 2*atomic mass ofC+2*atomic mass of H=2*12.01+2*1.007=26.0373 C3H8O 3*atomic mass of C+8*atomic mass of H+atomic mass of O=3*12.01+8*1.007+15.99=60.095 H2SO4 2*atomic mass of H+atomic mass of S+4*atomic mass of O=2*1.007+32.065+4*15.99=98.0785 NaOH atomic mass+Na+atomic mass of O+atomic mass of H=22.9897+15.99+1.007=39.997

Nov 21st, 2015

Nov 21st, 2015

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Nov 21st, 2015
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Nov 21st, 2015
Oct 20th, 2017
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