In a random sample, 136 of 400 persons given a flu vaccine experienced some discomfort.

I was asked to set up a 95% confidence interval for the true proportion of persons who will experience some discomfort. The problem is solved by I need help with interpretation.

We have p = 0.34, n = 400, and z = 1.96 for 95% confidence.

Thank you for the opportunity to help you with your question!

plus or minus a margin of error that our proportion is occurring . The result is called a confidence interval for the population proportion, p.

The formula for calculating confidence interval for a population proportion is given as the foollowing

p+_z*Squareroot (p(1-p)/n)

is the sample proportion, n is the sample size, and z* is the appropriate value from the standard normal distribution for your desired confidence level. certain confidence levels.

p =136/400=0.34 which is sample proportion from our sample n which is 400 z is the value from tables that shows the margin of error occurring which is from 95% confidence level

Please let me know if you need any clarification. I'm always happy to answer your questions.