In a random sample, 136 of 400 persons given a flu vaccine experienced some discomfort.
I was asked to set up a 95% confidence interval for the true proportion of persons who will experience some discomfort. The problem is solved by I need help with interpretation.
We have p = 0.34, n = 400, and z = 1.96 for 95%
Interval = 0.34 ± 1.96√[(0.34)(0.66)/400]
= 0.34 ± 1.96√0.000561
= 0.34 ± 1.96(0.023685439)
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plus or minus a margin of error that our proportion is occurring . The result is called a confidence interval for the population proportion, p.
The formula for calculating confidence interval for a population proportion is given as the foollowing
is the sample proportion, n is the sample size, and z* is the appropriate value from the standard normal distribution for your desired confidence level. certain confidence levels.
p =136/400=0.34 which is sample proportion from our sample n which is 400 z is the value from tables that shows the margin of error occurring which is from 95% confidence level
This is not what I asked . I've already resolved the problem and I know which formula to use. I need to find out what my answer means (interpretation )
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