Write an equation of the line that passes through (-3,3) and is perpendicular to the line 2y=8x-6.
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We write the equation 2y=8x-6 in the form y=mx+c as shown
Lines are perpendicular if when we multiply their slopes, we get −1
m1 * m2 =-1
The gradient for line one is 4
To get the equation, we use the point (-3,3)
Gradient=change in y/change in x
-1/4=(y-3)/(x - -3)
Thank You,for your help Doctor Ralph.
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