# Need calculus help with trigonometry

**Question description**

1) solve the equation on the interval, [0,2pi) .

6 tan^2 x -17 tanx +7 =0

2) solve the equation on the interval, [0,2pi)

sinx = -2/3

3) 2 tan^2x -2 =0

4) olve the equation on the interval, [0,2pi)

(cot u +1)(csc u -1) = 0

u = ?

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