HH = 25 Hh = 150 hh = 225
Calculate the frequencies of the H and h alleles. If these minnows were allowed to randomly mate
and produced a population of 2000 individuals, how many minnows of each genotype do you expect
to find in the offspring (assuming equal survivorship)?
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HH ,p^2=25/(25+150+225)=25/400 =.0625
Now,frequecny of H=p^2+1/2*2pq =.0625+.375/2 =.25
frequency of h=q^2+1/2*2pq =.5625+.375/2 =.75
Expected genotype frequency:
Expected number of individual of each genotype
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