A sample of 4 different calculators is randomly selected from a group 44 that are defective and 20 that have no defects. round to six decimal places.

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We have the total number of calculator =44+20=defective+non-defective=64

Now,the probability of selecting the defective calculator in the 1st attempt=44/64

Probability of selecting the second defective calculator in the second attempt =43/63

Simillarly in the 3rd attempt it will be 42/62

In the 4th attempt probability =41/61

Thus,Probability of selecting all the 4 calculator defective =(44/64)*(43/63)*(42/62)*(41/61)=.213655(answer)

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