# I need help with an algebra problem

Anonymous
account_balance_wallet \$5

### Question Description

psumanrec
School: Boston College

a)We have the sequence as

5(1+.5+.5^2+.5^3+.5^4+.5^5)

Here the sequence is in geometric progression with common ratio =.5

The first term is 1

So

=155/16 (as a fraction)

b)The term here are can be found out by substituting the value of j=1,2,...9

-4,-4^2,-4^3

So the sum =>-4+(-4)^2+(-4)^3+-------(-4)^9

So here the first term is -4 and total number of term =9

Common ratio,r=-4

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Anonymous
awesome work thanks

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