Need help wit a math word problem about rectangle auditorium seats

Mathematics
Tutor: None Selected Time limit: 1 Day

A rectangle auditorium seats 2337 people. The number of seat in each row exceeds the number of rows by 16. Find the number of seats in each row
Dec 1st, 2015

Thank you for the opportunity to help you with your question!

Let the no of  rows be x

So no of seats in each row = x+6

Total no of people= x (x+6)=2337

Or   x^2+6x =2337

x^2+6x-2337=0

We have to do the factors of 2337 in such a way that the difference is 6 and solve for  x then we can find x+6 which will give no of student in each row

Please let me know if you need any clarification. I'm always happy to answer your questions.
Dec 1st, 2015

It should be

x(x+16)=2337

x^2+16x-2337=0

Now to solve this, we should do the factors of 2337 in such a way that their difference is 16 and product is 2337

But I think there is some problem in the fig 2337 , so we can't solve for x and hence unable to solve and find the value of  x and the the no of x+16 which will give us no of seats

Dec 1st, 2015

x+16 will give us no of seats in each row...answer

Dec 1st, 2015

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