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compute
E="an odd number less 10."
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S={1,2,3,4,5,6,7,8,9,10}
As the sample space varies from 1 to 10 and the we have to find E such that it is an odd number less than 10.
So we have to find the odd number lying from from 1 to 10.
So the odd numbers are 1,3,5,7,9
E={1,3,5,7,9}
So the required probability =outcome/total event =5/10 =.5 (ans)
And the outcome E is the subset of the sample space.
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State the null and alternative hypotheses. Include a clear description of the populations and the variable.
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State a conclusion in the context of this problem.
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