Just a step by step processes required.
How many moles of NO3(-) ions are present in 533 mL of a 0.111 molar solution of Ca(NO3)2?
A) 0.0300 mol
B) 0.118 mol (correct answer)
D) 1.22 mol
I need an explanation please. I know the correct answer
Thank you for the opportunity to help you with your question!
Here we can calculate the moles of ca(No3)2 moles
it is 0.111 mol/dm^3* 533*10^(-3)dm^3
Then you can see , for every mole of Ca(No3)2 has two moles of No3^-
Then number of moles of No3^- =2*0.059163
Thank you for this and if you want any clarification , you are always welcome
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