P(|Z| > Z_0.01) = CP(|Z| > Z_0.01)+P(|Z| < -Z_0.01)

= P(sample mean - 9.80)*sqrt(4)/sigma > Z_0.01 + (9.81 -9.80)*sqrt(4)/sigma

P(sample mean - 9.80)*sqrt(4)/sigma < Z_0.01 + (9.81 -9.80)*sqrt(4)/sigma

that is the algebra in the deviation of the formula.

P(|Z| > Z_0.01) = o.372088166 (ecxel formula) =1-NORM.S.DIST(NORM.S.INV(0.99)+(0.01*2)/0.01,TRUE)+NORM.S.DIST(-NORM.S.INV(0.99)+(0.01*2)/0.01,TRUE)

you need to use the morm.s.dist and norm.inv functions

Thank you for the opportunity to help you with your question!

P { |Z| > 1} = P { Z < -0.01 } + P { Z < 0.01} = 0.4960 + 0.4960 = 0.992 = 99.2%.

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