Option 2: A professor states that in the United States the proportion of college students who own iPhones is .66. She then splits the class into two groups: Group 1 with students whose last name begins with A-K and Group 2 with students whose last name begins with L-Z. She then asks each group to count how many in that group own iPhones and to calculate the group proportion of iPhone ownership. For Group 1 the proportion is p1 and for Group 2 the proportion is p2. To calculate the proportion you take the number of iPhone owners and divide by the total number of students in the group. You will get a number between 0 and 1. What would you expect p1 and p2 to be? Do you expect either of these proportions to be vastly different from the population proportion of .66? Would you be surprised if p1 was different than p2? Would you be surprised if they were the same or similar? What statistical concept describes the relationship between the first letter of someone's last name and whether or not they own an iPhone? STUDENT 1: Respond to this students discussion post in response to Option 2 (above) I would expect that the percentage of iPhone users in both P1 and P2 to be similar. I think this might also depend on weather or not the college students are from the same area, or the same college. Overall, I'd expect them to be about the same even though P2 has more people in the sample. I would expect the proportion to be a little bit higher than the population proportion. I say this because I think college students tend to invest in technology a little bit more than the average person. They use computers and phones constantly, so they may be more inclined to go for the Apple products due to popularity. I would be pretty surprised if P1 was vastly different than P2. I wouldn't see why a random sample like this would yield two different results. This sample seems very random, so I would think it would yield similar results. I would not be surprised if they were similar at all. The concept in this problem is Probability, in this case .66 or 66%.