physics lab

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I need help in my physics 2 lab online I will give you the login information so you can go to the website and do the work and submit there once it done.

When heat energy (Q) is added to a material, the temperature of that material rises. The temperature is measured in degrees Celsius (°C) or in kelvins (K), while the specific heat of that material is measured in calories (cal) or joules (J). The International System of Units (SI) unit for specific heat is joules per kilogram kelvin (J/kg · K).

Heat capacity is the proportionality constant between the heat an object absorbs or loses and the resulting temperature change of the object.

Specific heat capacity (c) measures the amount of heat needed to increase the temperature of a mass of a material by one degree. The greater a material's specific heat, the more energy must be added to increase its temperature. For example, the specific heat of water is 1.00 cal/g · °C or 4180 J/kg · K. This value means that 1.00 calorie of heat is needed to raise one gram of water by one degree, or 4180 joules of heat is needed to raise one kilogram of water by one degree.

According to the law of conservation of energy, when two substances at different temperatures come into contact with one another, heat energy is transferred between them. For example, if you place a piece of hot metal into a container of cold water, the water and its container will become warmer, while the metal will become cooler, until an equilibrium temperature is reached.

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Tutor Answer

SkilledTutorZiss
School: UCLA

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PHYS 282 DL4
Specific Heat Capacit y of Met als

Final Report
St ude nt
Name

Bader Munim

St ude nt ID

50285

Le s s o n

Specific Heat C apacity of Metals

Ins t it ut io n

O cean C ounty C ollege

Se s s io n

2019SS10 PHYS 282 DL4

Co ur s e

PHYS 282 DL4

Ins t r uc t o r

Alison Lockm an

Exercise 1

Copyrigh t 2019 - H an ds-On Labs | h t t p://h olscien ce.com

1/ 7

1. Calc ulat e t he s pe c if ic he at o f e ac h me t al.

No t e : Ne gat ive Q r e pr e s e nt s he at lo s t by me t al, and po s it ive Q r e pr e s e nt s he at gaine d
by wat e r.
Metal 1

Q =25g*4.186J/g°c*2.3=240.695 J

m etal 2

Q =25g*4.186J/g°c*5.2=544.18J

Copyrigh t 2019 - H an ds-On Labs | h t t p://h olscien ce.com

2/ 7

2. So lve f o r t he s pe...

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