# Need algebra help for solving a value mixture problem using a system of linear equations

*label*Mathematics

*timer*Asked: Dec 18th, 2015

*account_balance_wallet*$5

### Question Description

Suppose that there are two types of tickets to a show: advanced and same day. The combined cost of one advance ticket and one same day ticket is $45. For one performance, 30 advance tickets and 40 same day tickets were sold. The total amount paid for the tickets was $1500. What was the price of each kind of ticket?

## Tutor Answer

Thank you for the opportunity to help you with your question!

advanced ticket=x

same day ticket=y

x+y=45-----------(1)

30x+40y=1500-------------(2)

form (1)

x=45-y

substitute in equation(2)

30(45-y)+40y=1500

solve for y

1350-30y+40y=1500

10y=150

y=$15

so

x=45-15

x=$30

**price of advanced ticket=$30**

**price of same day ticket=$15**

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