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We are given a function as

P(t) = 2900(0.91)^t

First Part:

To find the initial population size, put t=0

We get P(0) = 2900*1 = 2900

Second Part:

The function represents decay since 0.91<1.

Third Part:

To find the %change per hr, let us take P(t) and P(t+1)

So %change per hr = {P(t+1) - P(t)}/P(t) *100

%change = {2900(0.91)^(t+1) - 2900(0.91)^t}/2900(0.91)^t *100

%change = (0.91-1)*100

%change = -0.09*100

%change= -9% where negative sign signifies decay

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