i need help solving a trig question . i need to find the cos, sin and the missing degree and sides A=65 degrees, B=50 degrees, side c= 12. now i need to find sides a,b and degree C

Thank you for the opportunity to help you with your question!

b = 3.17, a = 12, C = 65

Explanation: The sum of all angles in a triangle add up to 180 degrees. Therefore, C = 180 -(50+65) = 65.

Since A and C are equal, the triangle is isoceles. An isoceles triangle has to opposite sides equal. a is opposite to c. Therefore, a = 12.

Drawing a perpendicular from B to line b, the perpendicular divides B into 2. Finding the product of a and Sin 25(ie 50/2) gives us half of b. Multiplying that by 2 gives us b, which is 3.17

Cos 65 = -0.5625

Cos 50 = 0.9650

Sin 65 = 0.8268

Sin 50 = -0.2624

Please let me know if you need any clarification. I'm always happy to answer your questions.