Need math help to Find equation of the perpendicular line to y=3x-1 through point (0, -2)?

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Dec 29th, 2015

Thank you for the opportunity to help you with your question!

Gradient of line perpendicular to the given line( p )= -(1/m)

where m is the gradient of the given line(i.e. y=3x-1) ; thus m=3

Therefore  p=-(1/3)

Now the line with gradient -1/3 and passing through (0,-2) is

y-(-2)=-(1/3)(x-0)

y+2=-(1/3)x

                              y=-2-x/3

Please let me know if you need any clarification. I'm always happy to answer your questions.
Dec 29th, 2015

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