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h) Force is defined as rate of change of momentum.
Now momentum of lineman = m1v1 = 120*6.5 = 780Kgm/s
time taken = 0.25s
hence force = 780/0.25 = 3120N
i) Let the final velocity of quarterback be v2, then
m1v1+m2v2 = 0
v2 = 7.091m/s
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