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its a questions about general chemistry lab please see the pictures that i attach,
its fine if you get the answers online but please make sure they are correct answers THANKS
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1. In Lab 10, we did paper chromatography. Please indicate the color of A, B, C and D 2. Why is it so important to mark the solvent front immediately in paper chromatography
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1 of 2
Date
Labtest2
1. In Lab 10, we did paper chromatography. Please indicate the color of A,B,C and D.
A
+ OH. FHOH
Cial + NH4
CHIP
D
H.CO
NOH
HC
CH
Np4 + 2NH2
NH
H.ch
NOH
H.
CH
2. Why is it important to mark the solvent front immediately in paper chromatography?
3. If the solvent front is 66mm and the ring front of an unknown is 33mm, what is the value?
4.
What is the color of Cu?? What is the color of Feb?
5. Which of the following molecules possess polar covalent bonds: Hg, N, HBr,HCN,CO,?
6. Draw the Lewis structure of NH, and determine the number of electron domain as well as its
geometry.
1
Name
Date
Labtest2
7. Calculate the formal charges of all atoms in No' and No.
2 of 2
ch of the following molecules possess polar covalent bonds: H, N, Br,HCN,CO,?
6. Draw the Lewis structure of NH, and determine the number of electron domain as well as its
geometry
Name
Date
Labtest2
7. Calculate the formal charges of all atoms in No' and NO.
in a gravimetric chloride analysis, it was found that 0.2516 g Agt was obtained
from an unknown that had a mass of 0.1567 g What is the percent of chloride in
this sample?
9. Write the net ionic equation of the following reaction
AgNO3(aq) + NaCl(aq)
AgCl) + NaNO (aq)
10. Write the net ionic equation of the following reaction:
Nalico (aq) + H-SOA (aq)
CO+ HO -Na so
2
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Explanation & Answer
Here we go
Surname 1
Your name
Professor’s name
Course
Date
General chemistry
Q1 answer is A
If 1 mL of a liquid has the mass of 1.52 g, then 30.0 mL has the mass of _____45.6_____ g.
Working
Density = 1.52 g/mL
1 mL of liquid has 1.52 gram
30 mL will have (30*1.52)=45.2 grams
Q2
Answer is A 100.090090
Q3. D chopping a log into sawdust
Q4. B 1.5*1023
no of atoms = W*6.023*10^23...
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