expanding the volume until the pressure reads 50.8kPa what is the new volume of air in the pump?
Thank you for the opportunity to help you with your question!
from Boyle's law, PV=K
this implies that P1*V1 = P2*V2
P1 = 203kPa, V1 = 0.5l
P2 = 50.8, V2= ?
applying the law,
203*0.5 = 50.8V2
thus V2 = (203*0.5)/50.8 =1.998L
thus your answer is 2.00L
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