a balloon contains 0.5L of air, question 4, chemistry homework

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Description

 101.5kPa  you squeeze it to a volume of0.25L  what is the pressure of air inside the balloon?

0.25kPa

50.8kPa

203kPa

102kPa

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Explanation & Answer

Thank you for the opportunity to help you with your question!

Again, P1V1 = P2V2

P1 = 101.5 kPa

P2 = ???

V1 = 0.5 L

V2 = 0.25 L

So we want to solve for P2

101.5kPa * .5 L = 0.25L *P2

P2 = 101.5kPa * 2

P2 = 203 kPa

Please let me know if you need any clarification. I'm always happy to answer your questions.


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