101.5kPa you squeeze it to a volume of0.25L what is the pressure of air inside the balloon?

0.25kPa

50.8kPa

203kPa

102kPa

Thank you for the opportunity to help you with your question!

from Boyle's law PV = k,

this implies that P1*V1 = P2*V2

P1 = 101.5kPa, V1 = 0.5L

P2 = ? , V2 =0.25L

making P2 the subject we have, P2 = (P1*V1) / V2

P2 =(101.5*0.5)/0.25 =203kPa

thus your answer is 203kPa

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