101.5kPa you squeeze it to a volume of0.25L what is the pressure of air inside the balloon?
Thank you for the opportunity to help you with your question!
from Boyle's law PV = k,
this implies that P1*V1 = P2*V2
P1 = 101.5kPa, V1 = 0.5L
P2 = ? , V2 =0.25L
making P2 the subject we have, P2 = (P1*V1) / V2
P2 =(101.5*0.5)/0.25 =203kPa
thus your answer is 203kPa
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?