you have 0.5L of air at 203K in an expandable container at constant pressure, chemistry homework

label Chemistry
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you heat the container to 273K  what is the volume of air?

0.25L

0.67L

1.5L

0.37L

Jan 15th, 2016

Thank you for the opportunity to help you with your question!

v1 / t1 = v2 / t2

v1 = 0.5 L

t1 = 203K

t2 = 273 K 

v2 = ???

So you want to solve for v2

v2 = v1 * t2 / t1

V2 = 0.5L * 273K / 203 K

V2 = 0.67 L

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jan 15th, 2016

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