a balloon contains 0.5L of air Chemistry question 4

label Chemistry
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schedule 1 Day
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273K its volume increases to volume of 0.75L 

205K

137K

410K

182K

Jan 15th, 2016

Thank you for the opportunity to help you with your question!

V1/T1=V2/T2.

V1=0.5L

T1=273K

V2=0.75

T2=T1*V2/V1

T2=273*0.75/0.5

T2=410K

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jan 15th, 2016

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