of 203k Pa and a temperature of 203 K You heat the container to 273 K what is the final pressure of the air
Thank you for the opportunity to help you with your question!
As the container is rigid, so volume is constant
Hence P2/P1 = T2/T1
P2/203 = 273/203
P2 = (273/203)*203
P2 = 273 kPa
Hence correct option is 273 kPa
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?