What is the magnitude of the electric field produced by a charge of magnitude 6? Physics homework

Physics
Tutor: None Selected Time limit: 1 Day

Jan 16th, 2016

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E = kQ/r^2

k=8.99 × 109 Nm2/C2

Q=6.80*10^-6

thus at 1.00m, E= (8.99 × 109 * 6.80*10^-6)/1^2

thus E=6.11*10^4

at 2.00m, E= (8.99 × 109 * 6.80*10^-6)/2^2

E=1.53*10^4

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Jan 16th, 2016

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