Description
Consider the reaction following reaction. Answer question B.
(b) Calculate ΔG° at 298 K if the reaction mixture consists of 7.8 atm of H2, 0.049 atm of P4, and 0.24 atm of PH3.
Explanation & Answer
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for part 1;
rate of PH3 = 0.0027 / 1.5 = 0.0018 mol/L
rate of P4 = 1/4 * 0.0018 = 0.00045 mol/L
rate of H2 = 6/4 * 0.0018 = 0.0027 m
for part 2;
The dependence of free energy on pressure is given by the formula;
ΔG = ΔG° + RT ln Q
where Q = P^2(NH3) / P(N2) x P^3(H2)
Q = (0.65)^2 / (1.9)(1.6)^3
Q = 0.054
ΔG° = - 33.3 kJ/mol
T = 298 K
R = 8.3145 J/K.mol = 0.0083145 kJ/K.mol
ΔG = - 33.3 + (0.0083145)(298) ln(0.054)
ΔG = - 33.3 + (0.0083145)(298) (- 2.918)
ΔG = - 33.3 - 7.23 = - 40.53 kJ/mol
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