Chemistry Reaction, Thermochemistry homework

Chemistry
Tutor: None Selected Time limit: 1 Day

Consider the reaction following reaction. Answer question B.

6 H2(g) + P4(g) → 4 PH3(g)
(a) Using data from Appendix C, calculate ΔG° at 298 K.
 
Given: 29.2 kJ

(b) Calculate ΔG° at 298 K if the reaction mixture consists of 7.8 atm of H20.049 atm of P4, and 0.24 atm of PH3.
Jan 16th, 2016

Thank you for the opportunity to help you with your question!

for part 1;

rate of PH3 = 0.0027 / 1.5 = 0.0018 mol/L

rate of P4 = 1/4 * 0.0018 = 0.00045 mol/L

rate of H2 = 6/4 * 0.0018 = 0.0027 m

for part 2;

The dependence of free energy on pressure is given by the formula;

ΔG = ΔG° + RT ln Q

where Q = P^2(NH3) / P(N2) x P^3(H2)

Q = (0.65)^2 / (1.9)(1.6)^3
Q = 0.054

ΔG° = - 33.3 kJ/mol
T = 298 K
R = 8.3145 J/K.mol = 0.0083145 kJ/K.mol

ΔG = - 33.3 + (0.0083145)(298) ln(0.054)
ΔG = - 33.3 + (0.0083145)(298) (- 2.918)
ΔG = - 33.3 - 7.23 = - 40.53 kJ/mol

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jan 16th, 2016

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