Magnitude of electric field homework help

Physics
Tutor: None Selected Time limit: 1 Day

Jan 17th, 2016

Thank you for the opportunity to help you with your question!

F = qE 

TsinQ = F

TcosQ = mg

tanQ = F/mg = 0.255/(0.025*9.8)  = 1.0408

Q= 46.145 degrees

a) E= F/q = 0.255/3.10 uC = 8.23 x10^4 N/C

b) Q= 46.145 degrees


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Jan 17th, 2016

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