Magnitude of electric field homework help

Physics
Tutor: None Selected Time limit: 1 Day

Jan 17th, 2016

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E = kQ/d^2

Where k = 9.0x10^9 N.M^2/C^2

Part a

Q = 6.8 uC

d = 1m

Thus 

E = 9.0×10^9 × 6.8 × 10^-6/1^2 = 6.12×10^4 N/C

Part b

Q = 6.8uC

d= 2m 

Thus;

E = 9.0×10^9 × 6.8 × 10^-6/2^2 =1.53 N/C

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jan 17th, 2016

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