two point charges of equal magnitude, physics homework

Physics
Tutor: None Selected Time limit: 1 Day

Jan 17th, 2016

Thank you for the opportunity to help you with your question!

Lets assume the charges are q1 and q2 and both are equal to q.

d = 7.2 cm = 0.072m

E = 41N/C

But E = E1 + E2

E = kq/d^2

Thus;

41 =(9.0×10^9×q/0.036^2)+(9.0×10^9×q/0.036^2)

1.3889×10^13 × q = 41

Therefore q = 41÷ 1.3889×10^13 = 2.952×10^-12 C


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Jan 17th, 2016

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