To find the x and y components, just use trigonometry (note that the direction of the field is away from the charges, since the charges are positive, so q1‘s x component will be negative, q2‘s x component will be positive, and both y components will be positive:

F1, x = F1 * cos(θ1) F1, x = 0.18 * -cos(36.87) F1, x = -0.144 N/C

F1, y = F1 * sin(θ1) F1, y = 0.18 * sin(36.87) F1, y = 0.108 N/C

F2, x = F2 * cos(θ2) F2, x = 0.24 * cos(53.13) F2, x = 0.144 N/C

F2, y = F2 * sin(θ2) F2, y = 0.24 * sin(53.13) F2, y = 0.192 N/C

So the sum of the x components is 0 (+0.144 from q2, -0.144 from q1. The sum of the y components is 0.300 (0.144 + 0.192):

0,0.300 N/C

Part B:

The sum of the x components is -0.288(-0.144 from q2, -0.144 from q1. The sum of the y components is 0.300 (0.144 - 0.192):

-0.288, -0.048Please let me know if you need any clarification. I'm always happy to answer your questions.