Description
A parallel-plate capacitor has plates with an area of 0.012 m^2 and a separation of 0.83 mm.Calculate the potential difference for the case where the dielectric constant is 4.2.

Explanation & Answer

Thank you for the opportunity to help you with your question!
Given A=0.012m²
d=0.00083m
εr=4.2
εo=8.854e-12F/m
Q=4.1μC
V = Q/C = Q·d/(εr·εo·A) = 7.629kV
Please let me know if you need any clarification. I'm always happy to answer your questions.