Calculate the potential difference for the case where the dielectric constant is 4.2. Physics homework help

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Phgrr2016

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A parallel-plate capacitor has plates with an area of 0.012 m^2 and a separation of 0.83 mm.Calculate the potential difference for the case where the dielectric constant is 4.2.

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Explanation & Answer

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Given A=0.012m²

d=0.00083m

εr=4.2

εo=8.854e-12F/m

Q=4.1μC 

V = Q/C = Q·d/(εr·εo·A) = 7.629kV

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