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1.A 100 kg man supports all his weight on a snowshoe with an area of 50 cm2. What pressure is exerted on the snow in N/m2?

(1 cm2= 1x10-4 m2)

2.What’s the pressure at a depth of 120 m in ocean?

3.In a hydraulic system, a force of 400 N is exerted on a piston with an area of 0.001 m2. The load-bearing piston in the system has an area of 0.2 m2.

a) What’s the pressure in the hydraulic fluid?

b) What’s the magnitude of the force exerted on the loading piston?

4.A rock with a volume of 0.2 m3 is fully submerged in water having a density of 1000 kg/m3. What is the buoyant force acting on the rock?

5.A water stream moving with a speed of 4 m/s in a small pipe with area of 0.05 m2 reaches a large pipe with area of 0.2 m2. What’s the speed of water in the large pipe?

6. What’s the principle of hydraulic jack?

Tags:
physics
CUNY Borough of Manhattan Community College
PHY108
hydraulic fluid
buoyant force
hydraulic machinery
antiwear protection

Homework problems: Chapter 9
1. A 100 kg man supports all his weight on a snowshoe with an area
of 50 cm2. What pressure is exerted on the snow in N/m2?
(1 cm2= 1x10-4 m2)
2. What’s the pressure at a depth of 120 m in ocean?
3. In a hydraulic system, a force of 400 N is exerted on a piston with
an area of 0.001 m2. The load-bearing piston in the system has an
area of 0.2 m2.
a) What’s the pressure in the hydraulic fluid?
b) What’s the magnitude of the force exerted on the loading
piston?
4. A rock with a volume of 0.2 m3 is fully submerged in water having
a density of 1000 kg/m3. What is the buoyant force acting on the
rock?
5. A water stream moving with a speed of 4 m/s in a small pipe with
area of 0.05 m2 reaches a large pipe with area of 0.2 m2. What’s
the speed of water in the large pipe?
6. What’s the principle of hydraulic jack?
...

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Attached.

Homework problems: Chapter 9

1. A 100 kg man supports all his weight on a snowshoe with an area

of 50 cm2. What pressure is exerted on the snow in N/m2?

(1 cm2= 1x10-4 m2)

𝑃=

𝑃=

𝑚𝑔

𝐴

100 ⋅ 10

. 005

𝑃 = 200,000

𝑁

𝑚2

2. What’s the pressure at a depth of 120 m in ocean?

𝑃 = 𝑃𝑜 + 𝜌𝑔ℎ

𝑃 = 100000 + 1000 ⋅ 10 ⋅ 120

𝑃 = 100000 + 1200000

𝑃 = 1,300,000 𝑃𝑎

3. In a hydraulic system, a force of 400 N is exerted on a piston with

an area of 0.001 m2. The load-bearing piston in the system has an

area of 0.2 m2.

a) What’s the pressure in the hydraulic fluid?

𝑃=

𝐹

𝐴

400

...

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