Resistors, r1 and r2, in series with an ideal battery have voltmeter measurements of 2V, 3V, and 6V. What are the actual resistor voltages?
Since the battery is ideal, the actual voltages across individual resistors are governed by Ohm's Law.
Voltage across r1 = V * (r1 / (r1 + r2)) and voltage across r2 = V * (r2 / (r1 + r2))
This comes out to:
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